ARRAYS

uint8_t studentsAge[100]; // 100 elements in the array

Things to note:

• studentAge is a base pointer to a 100 data items of type uint8_t
• Data type of studentAge is uint8_t*
• Data type of the items stored is uint8_t

Since array's name is just a base pointer, you can access N's element by incrementing a pointer and then dereferencing it. Example accessing 1st element (studentsAge[1]):

printf("2nd element is: %u", *(studentAge+1)); // Incrementing a base pointer and dereferencing it

This is the same as:

printf("2nd element is: %u", studentAge[1]); // 1 - is an offset

#include <stdio.h>
#include <stdint.h>
 
void array_display(uint8_t *pArray, uint32_t nItems);
 
int main(void)
{
	uint8_t data[10] = {0x01, 0x02, 0x03};
	uint32_t nItems = sizeof(data) / sizeof(uint8_t);
 
	array_display(data, nItems);
 
	getchar();
	getchar();
 
	return 0;
}
 
void array_display(uint8_t *pArray, uint32_t nItems)
{
	for(uint32_t i = 0; i < nItems; i++)
	{
		printf("Element: %u,\tvalue:%#x\n", i, pArray[i]);
	}
}

If we want to print an array with an offset (e.g. starting from 2nd element) - just send the address of the second element to the function:

array_display((data+2), (nItems-2));

Or like this (sending address of the second element):

array_display(&data[2]), (nItems-2));